成都创新互联网站制作重庆分公司

利用Java在将整型数与byte[]数组进行转换-创新互联

这篇文章将为大家详细讲解有关利用Java在将整型数与byte[]数组进行转换,文章内容质量较高,因此小编分享给大家做个参考,希望大家阅读完这篇文章后对相关知识有一定的了解。

创新互联公司IDC提供业务:服务器托管,成都服务器租用,服务器托管,重庆服务器租用等四川省内主机托管与主机租用业务;数据中心含:双线机房,BGP机房,电信机房,移动机房,联通机房。

具体如下:

工作项目需要在java和c/c++之间进行socket通信,socket通信是以字节流或者字节包进行的,socket发送方须将数据转换为字节流或者字节包,而接收方则将字节流和字节包再转换回相应的数据类型。如果发送方和接收方都是同种语言,则一般只涉及到字节序的调整。而对于java和c/c++的通信,则情况就要复杂一些,主要是因为java中没有unsigned类型,并且java和c在某些数据类型上的长度不一致。

针对这种情况,本文整理了java数据类型和网络字节流或字节包(相当于java的byte数组)之间转换方法。实际上网上这方面的资料不少,但往往不全,甚至有些有错误,于是就花了点时间对java整型数和网络字节序的byte[]之间转换的各种情况做了一些验证和整理。整理出来的函数如下:

public class ByteConvert {
  // 以下 是整型数 和 网络字节序的 byte[] 数组之间的转换
  public static byte[] longToBytes(long n) {
    byte[] b = new byte[8];
    b[7] = (byte) (n & 0xff);
    b[6] = (byte) (n >> 8 & 0xff);
    b[5] = (byte) (n >> 16 & 0xff);
    b[4] = (byte) (n >> 24 & 0xff);
    b[3] = (byte) (n >> 32 & 0xff);
    b[2] = (byte) (n >> 40 & 0xff);
    b[1] = (byte) (n >> 48 & 0xff);
    b[0] = (byte) (n >> 56 & 0xff);
    return b;
  }
  public static void longToBytes( long n, byte[] array, int offset ){
    array[7+offset] = (byte) (n & 0xff);
    array[6+offset] = (byte) (n >> 8 & 0xff);
    array[5+offset] = (byte) (n >> 16 & 0xff);
    array[4+offset] = (byte) (n >> 24 & 0xff);
    array[3+offset] = (byte) (n >> 32 & 0xff);
    array[2+offset] = (byte) (n >> 40 & 0xff);
    array[1+offset] = (byte) (n >> 48 & 0xff);
    array[0+offset] = (byte) (n >> 56 & 0xff);
  }
  public static long bytesToLong( byte[] array )
  {
    return ((((long) array[ 0] & 0xff) << 56)
       | (((long) array[ 1] & 0xff) << 48)
       | (((long) array[ 2] & 0xff) << 40)
       | (((long) array[ 3] & 0xff) << 32)
       | (((long) array[ 4] & 0xff) << 24)
       | (((long) array[ 5] & 0xff) << 16)
       | (((long) array[ 6] & 0xff) << 8)
       | (((long) array[ 7] & 0xff) << 0));
  }
  public static long bytesToLong( byte[] array, int offset )
  {
    return ((((long) array[offset + 0] & 0xff) << 56)
       | (((long) array[offset + 1] & 0xff) << 48)
       | (((long) array[offset + 2] & 0xff) << 40)
       | (((long) array[offset + 3] & 0xff) << 32)
       | (((long) array[offset + 4] & 0xff) << 24)
       | (((long) array[offset + 5] & 0xff) << 16)
       | (((long) array[offset + 6] & 0xff) << 8)
       | (((long) array[offset + 7] & 0xff) << 0));
  }
  public static byte[] intToBytes(int n) {
    byte[] b = new byte[4];
    b[3] = (byte) (n & 0xff);
    b[2] = (byte) (n >> 8 & 0xff);
    b[1] = (byte) (n >> 16 & 0xff);
    b[0] = (byte) (n >> 24 & 0xff);
    return b;
  }
  public static void intToBytes( int n, byte[] array, int offset ){
    array[3+offset] = (byte) (n & 0xff);
    array[2+offset] = (byte) (n >> 8 & 0xff);
    array[1+offset] = (byte) (n >> 16 & 0xff);
    array[offset] = (byte) (n >> 24 & 0xff);
  }
  public static int bytesToInt(byte b[]) {
    return  b[3] & 0xff
        | (b[2] & 0xff) << 8
        | (b[1] & 0xff) << 16
        | (b[0] & 0xff) << 24;
  }
  public static int bytesToInt(byte b[], int offset) {
    return  b[offset+3] & 0xff
        | (b[offset+2] & 0xff) << 8
        | (b[offset+1] & 0xff) << 16
        | (b[offset] & 0xff) << 24;
  }
  public static byte[] uintToBytes( long n )
  {
    byte[] b = new byte[4];
    b[3] = (byte) (n & 0xff);
    b[2] = (byte) (n >> 8 & 0xff);
    b[1] = (byte) (n >> 16 & 0xff);
    b[0] = (byte) (n >> 24 & 0xff);
    return b;
  }
  public static void uintToBytes( long n, byte[] array, int offset ){
    array[3+offset] = (byte) (n );
    array[2+offset] = (byte) (n >> 8 & 0xff);
    array[1+offset] = (byte) (n >> 16 & 0xff);
    array[offset]  = (byte) (n >> 24 & 0xff);
  }
  public static long bytesToUint(byte[] array) {
    return ((long) (array[3] & 0xff))
       | ((long) (array[2] & 0xff)) << 8
       | ((long) (array[1] & 0xff)) << 16
       | ((long) (array[0] & 0xff)) << 24;
  }
  public static long bytesToUint(byte[] array, int offset) {
    return ((long) (array[offset+3] & 0xff))
       | ((long) (array[offset+2] & 0xff)) << 8
       | ((long) (array[offset+1] & 0xff)) << 16
       | ((long) (array[offset]  & 0xff)) << 24;
  }
  public static byte[] shortToBytes(short n) {
    byte[] b = new byte[2];
    b[1] = (byte) ( n    & 0xff);
    b[0] = (byte) ((n >> 8) & 0xff);
    return b;
  }
  public static void shortToBytes(short n, byte[] array, int offset ) {
    array[offset+1] = (byte) ( n    & 0xff);
    array[offset] = (byte) ((n >> 8) & 0xff);
  }
  public static short bytesToShort(byte[] b){
    return (short)( b[1] & 0xff
           |(b[0] & 0xff) << 8 );
  }
  public static short bytesToShort(byte[] b, int offset){
    return (short)( b[offset+1] & 0xff
           |(b[offset]  & 0xff) << 8 );
  }
  public static byte[] ushortToBytes(int n) {
    byte[] b = new byte[2];
    b[1] = (byte) ( n    & 0xff);
    b[0] = (byte) ((n >> 8) & 0xff);
    return b;
  }
  public static void ushortToBytes(int n, byte[] array, int offset ) {
    array[offset+1] = (byte) ( n    & 0xff);
    array[offset] = (byte)  ((n >> 8) & 0xff);
  }
  public static int bytesToUshort(byte b[]) {
    return  b[1] & 0xff
        | (b[0] & 0xff) << 8;
  }
  public static int bytesToUshort(byte b[], int offset) {
    return  b[offset+1] & 0xff
        | (b[offset]  & 0xff) << 8;
  }
  public static byte[] ubyteToBytes( int n ){
    byte[] b = new byte[1];
    b[0] = (byte) (n & 0xff);
    return b;
  }
  public static void ubyteToBytes( int n, byte[] array, int offset ){
    array[0] = (byte) (n & 0xff);
  }
  public static int bytesToUbyte( byte[] array ){
    return array[0] & 0xff;
  }
  public static int bytesToUbyte( byte[] array, int offset ){
    return array[offset] & 0xff;
  }
  // char 类型、 float、double 类型和 byte[] 数组之间的转换关系还需继续研究实现。
}

分享名称:利用Java在将整型数与byte[]数组进行转换-创新互联
文章链接:http://cxhlcq.com/article/dpidio.html

其他资讯

在线咨询

微信咨询

电话咨询

028-86922220(工作日)

18980820575(7×24)

提交需求

返回顶部