何必这么麻烦呢...
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问题一(判断回文数):
如下代码:
Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
Dim input As Integer = Val(TextBox1.Text)
If IsHui(input) Then
ListBox1.Items.Add("★" TextBox1.Text)
Else
ListBox1.Items.Add(TextBox1.Text)
End If
End Sub
Private Function IsHui(ByVal s As Integer) As Boolean
Dim input As String = s.ToString
Dim Re_input As String = StrReverse(input)
If input = Re_input Then Return True
Return False
End Function
问题二(判断因子之和是不是质数):
如下代码:
'判断是不是质数
Private Function prime(ByVal n As Integer) As Boolean
For i = 2 To n - 1
If n Mod i = 0 Then
Return False
End If
Next
Return True
End Function
'求因子
Private Function GetFactor(ByVal s As Integer) As Integer()
Dim results(0) As Integer
Dim count As Integer = 0
For i = 1 To s
If s Mod i = 0 Then
ReDim Preserve results(count)
results(count) = i
count += 1
End If
Next
Return results
End Function
Private Sub Button2_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button2.Click
Dim input As Integer = Val(TextBox2.Text)
Dim Factors() As Integer = GetFactor(input)
Dim sum As Integer
For i = 0 To Factors.Length - 1
sum += Factors(i)
Next
If prime(sum) Then
MessageBox.Show("这个数因子之和为质数!")
Else
MessageBox.Show("这个数因子之和不是质数!")
End If
End Sub
结果输出上可能和题目要求有所不同,,自己变通一下,
有任何问题请Hi我.
您可以选择使用CheckListBox控件。CheckListBox支持多选。
由于不清楚您用什么语言，所以我写了VB.net 、C#.net
vb.net Code
' Determine if there are any items checked.
If CheckedListBox1.CheckedItems.Count 0 Then
' If so, loop through all checked items and print results.
Dim x As Integer
Dim s As String = ""
For x = 0 To CheckedListBox1.CheckedItems.Count - 1
s = s "Checked Item " (x + 1).ToString " = " CheckedListBox1.CheckedItems(x).ToString ControlChars.CrLf
Next x
MessageBox.Show(s)
End If
C#.net Code
// Determine if there are any items checked.
if(checkedListBox1.CheckedItems.Count != 0)
{
// If so, loop through all checked items and print results.
string s = "";
for(int x = 0; x = checkedListBox1.CheckedItems.Count - 1 ; x++)
{
s = s + "Checked Item " + (x+1).ToString() + " = " + checkedListBox1.CheckedItems[x].ToString() + "\n";
}
MessageBox.Show (s);
}
vb.net Code
Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
Dim selectstr As String = ""
For i As Integer = 0 To Me.CheckedListBox1.Items.Count - 1
If Me.CheckedListBox1.GetItemChecked(i) Then
selectstr = Me.CheckedListBox1.Items(i).ToString
End If
Next
MsgBox(selectstr)
End Sub
希望能帮到您。
额 这 我倒是知道一款asp.net的=。 =叫KesionIexam它可以实现单选题多选题和简答题，还有填空题判断题等等，只要按格式把试题编写好整卷录入就可以在前台看到它咯！
如果需要讲详细一点,那就加我QQ531412815
第4题,潜在的错误,这里的错误不是常规错误,属于那种只有在运行是才知道的错误:
Catch ex As Exception
MsgBox(ex.StackTrace)
'永远不会查找下面的错误
Catch ex As ArgumentNullException
MsgBox("Input Test box cannot be null.")
Catch ex As OverflowException
MsgBox("Input Test box 2 cannot be zero!")
Catch ex As FormatException
MsgBox("Input Test box should be numeric format!")
结构化错误处理永远达不到下面这里,因为Catch ex As Exception 已经处理了所有错误.
第5题：
00123
1000 60.50
2000 60.00
3500 59.50
---- -----
6500 60.00
00124
3000 60.50
---- -----
3000 60.50
00125
2000 59.50
1000 58.00
---- -----
3000 58.75
就是按照Ref_ID 分类，有一种方法就是按照Ref_ID 分组，也就是使用SQL语言，不过这里需要该很多，
我就不用了，那么就稍微复杂一点，使用FIND方法,不过有一点必须注意REF_ID必须排序，因为数据库中
已经排好序了，我就不用排了。
Dim rst as ADODB.Recordset
dim refID as string
Rst = GetRecordset
Do While Not rst.EOF
refid=rst(0)
Console.writeline(rst.Fields("Ref_ID")
do
Console.writeline rst.Fields("Qty") vbcrlf rst.Fields("Price"))
rst.MoveNext()
loop while rst(0)=refid
Loop
第6题：就是从一个集合中取元素输出的问题
比较简单的办法就是使用递归
以下是使用VB的方法(可以移植到VB.NET上,因为我对VB.NET的数组到现在还不太会,所以就将就一下)
Dim bUse() As Boolean
Dim lStr() As String * 1
Dim nCount As Byte
-----------------------------------------------------------------------------------
Public Sub Combination(lstStr As String)
Dim i As Byte
Dim j As Byte
Dim StrLen As Byte
StrLen = Len(lstStr)
ReDim bUse(1 To StrLen) As Boolean
ReDim lStr(1 To StrLen) As String * 1
For i = 1 To StrLen
lStr(i) = Mid(lstStr, i, 1)
Next
For i = 1 To StrLen
nCount = i
GoWith StrLen, 1, 0, ""
Next
End Sub
------------------------------------------------------------------------------------
Public Sub GoWith(ECount As Byte, nStart As Byte, Deep As Byte, lastStr As String)
Dim i As Byte
If Deep = nCount Then
Debug.Print lastStr
Exit Sub
End If
For i = nStart To ECount
If Not bUse(i) Then
bUse(i) = True
GoWith ECount, i, Deep + 1, lastStr lStr(i)
bUse(i) = False
End If
Next
End Sub
--------------------------------------------------------------------------------------
Private Sub Form_Load()
Combination "wxyz"
End Sub
--------------------------------------------------------------------------------------
其中GOWITH是真正的递归函数,而Combination是用来预处理字符的
全局变量:
BUSE：用来确定是否使用过这个元素
lSTR：用来保存字符元素
NCOUNT：用来限制递归函数的深度，换句话说，就是输出元素组中的元素个数
实际测试成功，另外我对前三题很感兴趣，希望能够传给我
Private Sub ListBox1_SelectedIndexChanged(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles ListBox1.SelectedIndexChanged
MessageBox.Show(ListBox1.SelectedItem.ToString)
End Sub
Private Sub Form1_Load(ByVal sender As Object, ByVal e As System.EventArgs) Handles Me.Load
For i As Integer = 0 To 10
ListBox1.Items.Add(i.ToString)
Next
End Sub
'''''''选择多项
Private Sub Form1_Load(ByVal sender As Object, ByVal e As System.EventArgs) Handles Me.Load
For i As Integer = 0 To 10
ListBox1.Items.Add(i.ToString)
Next
ListBox1.SelectionMode = SelectionMode.MultiSimple
End Sub
Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
Dim item
For Each item In ListBox1.SelectedItems
MessageBox.Show(item.ToString)
Next
End Sub
asp:RadioButton ID="RadioButton1" runat="server" Text="A." GroupName="group1"/
asp:RadioButton ID="RadioButton2" runat="server" Text="B." GroupName="group1" /
asp:RadioButton ID="RadioButton3" runat="server" Text="C." GroupName="group1" /
asp:RadioButton ID="RadioButton4" runat="server" Text="D." GroupName="group1" /
div
asp:CheckBox ID="CheckBox1" runat="server" Text ="A." /
asp:CheckBox ID="CheckBox2" runat="server" Text ="B." /
asp:CheckBox ID="CheckBox3" runat="server" Text ="C." /
asp:CheckBox ID="CheckBox4" runat="server" Text ="D." /
/div
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