成都创新互联网站制作重庆分公司

递归求阶乘

def factorial(n):
    result = n
    for i in range(1,  n):
        result *= i
    return result
number = int(input("请输入一个正整数:"))

result = factorial(number)
print("%d的阶乘是:%d" %(number, result))

-----
def factorial(n):
    if n == 1:
        return 1
    else:
        return n* factorial(n - 1)
number = int(input("请输入一个正整数:"))

result = factorial(number)
print("%d的阶乘是:%d" %(number, result))

斐波那契数列

def f(n):
    if n == 1:
        ret = 0
    elif n == 2:
        ret = 1
    else:
        ret = f(n-1)+f(n-2)
    return ret
print(f(4))
def f(n):
    if n == 1:
        return 0
    elif n == 2:
        return 1
    return f(n-1)+f(n-2)
print(f(5))

网站名称:递归求阶乘
转载注明:http://cxhlcq.com/article/jdicos.html

其他资讯

在线咨询

微信咨询

电话咨询

028-86922220(工作日)

18980820575(7×24)

提交需求

返回顶部